[jacks]

Solution of following System of equations is

(1)

 \( y^3-6x^2+12x-8 = 0 \)

\( z^3-6y^2+12y-8 = 0 \)

\( x^3-6z^2+12z-8 = 0 \)


(2)

\( 2y^3+2x^2+3x+3 = 0 \)

\( 2z^3+2y^2+3y+3 = 0 \)

\( 2x^3+z^2+3z+3 = 0 \)

(3)

\( y^3-9x^2+27x-27 = 0 \)

\( z^3-9y^2+27y-27 = 0 \)

\( x^3-9z^2+27z-27 = 0 \)

[taka]

I dont know it exactly but maybe the results are

a) \( (x,y,z) = (2,2,2) \)

c) \(  (x,y,z) = (3,3,3) \)