[marinavzqz]

Show  that  if \( f:X\to Y \) is onto and \( \Bbb F \) is a filter on \( X \) then  the  image  filter\(  f(\Bbb F) =\{f(F):F\in \Bbb F\} \), i.e.,\( \{f(F):F\in \Bbb F\} \) is a filter.